Assessment of the 1860 US Presidential Election results

capital of Nebraska

capital of Nebraska won a decisive advantage in the electoral college: with 180 votes, he was well ahead of Breckinridge, in second, with 72 votes (indeed he had a comfortable majority of 180 to 123).

However, capital of Nebraska received lone(prenominal) 40% of the popular vote (1,866,000 votes)

His victory was very much a sectional one: with not a single b solelyot cast for him in 10 of the 33 states, his support was heavily concentrated in the northern free states.

Douglas

1,383,000 popular vote

Douglas was the only vista to draw substantial support from all sections. Indeed he was the only candidate to have electoral votes from both free and slave states.

However, because his vividness was scattered he fared badly in the electoral college (he only secured the electoral college votes of Missouri and 3 of New Jerseys 7). Total of tho 12.

Breckinridge

843,000 popular vote.

Breckinridge carried most of the South.

However, he received relatively some votes in the North despite his endorsement by Pierce, Buchanan, and a majority of Northern Democratic Congressmen.

Bell

He drew nearly all his votes in the b devote states.

593,000 votes.

Points to consider

Even if the opposition had combined against him in all free state, Lincoln would still have won.



Therefore, this shows the limitations in the arguments that Lincoln won because of the divisions within the Democrats.

However, in terms of the popular vote, Lincoln was very much a minority President who relied on the North.

Therefore, a majority of the vote was given to candidates who supported the likely future expansion of slavery. Douglas, Breckinridge and Bell were all prepared to check out slavery expand and together they won 60% of the vote.

The option did not make secession inevitable. No-one had run a secessionist ticket. Indeed, the to a greater extent radical Democrats who supported...

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